Rick Hasen has this list of amicus curiae briefs in Gill v Whitford, 16-1161, that are on the side that opposes the Wisconsin legislative districts. The list includes dozens of political scientists and other academicians. It is believed that no political scientist has filed any amicus on the side of the state of Wisconsin.
Attention ALL lawyers and profs (and BAN folks) —
1/2 or less votes x 1/2 gerrymander areas = 1/4 or less CONTROL — since the 1964 SCOTUS gerrymander cases — whoever or whatever is rigging the area lines.
Brain dead ignorance about RFG in the dead 1787 USA Const – Art. IV, Sec. 4.
—
PR and AppV — regardless of ALL math M-O-R-O-N lawyers, judges and esp. profs — law, polisci, math, history, etc.
See SCOTUS blog for ALL of the briefs.
Prof Hasen is more than a little left biased.
Actually, the cited post from Prof. Hasen is an update of the previous day’s post, which he said was intended to complete the list of amici for the challengers; that previous post, which does also list amici for the state, is here:
http://electionlawblog.org/?p=94598
The SCOTUSblog “home page” for the case is here:
http://www.scotusblog.com/case-files/cases/gill-v-whitford/
http://www.brennancenter.org/legal-work/whitford-v-gill
has ALL of the briefs plus lower court stuff.
LOTS of very repetitive left/right stuff in the briefs.
Trump received 50.41% of the Trump-Clinton vote in Wisconsin in 2016.
If each voter had their own district, Trump would carry 50.41% of the districts.
Now imagine if each district had three voters, assigned randomly. The results would be 0:3, 1:2, 2:1, or 3:0.
How many districts would Trump carry?
50%
50.41%
50.82%
50.61%
100%
Ok how about if each district had 11 voters assigned randomly (we choose odd numbers to avoid tie votes)
50%
50.41%
50.82%
51.10%
100%
Perhaps 101 voters per district.
50%
50.41%
50.82%
53.28%
100%
How about 1001 voters per district.
50%
50.41%
50.82%
60.19%
100%
Or perhaps 10,001 voters per district.
50%
50.41%
50.82%
79.28%
100%
Or perhaps 28,159 voters per district (chosen so there are 99 districts, the same number as Wisconsin has Assembly districts).
50%
50.41%
50.82%
91.45%
100%
The correct answer is the 4th answer in all cases. With 50.41% of the popular vote, Trump should carry 91.45% of 99 districts (90.5 districts).
Basic PR for all BAN folks and brain dead lawyers and judges — legislative body elections —
Total Members x Party Votes / Total Votes = Party Members.
Party Votes / Total Votes is the *P.R.* fraction.
Copy and paste on your monitor.
99 x 0.5041 = 49.91 >>> 50 Members/seats
PR and AppV